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Question
A clock regulated by seconds pendulum, keeps correct time. During summer, length of pendulum increases to 1.005 m. How much will the clock gain or loose in one day?
(g = 9.8 m/s2 and π = 3.142)
Solution
Given: L = 1.005 m, g = 9.8 m/s2
To find: Loss in period (ΔT)
Formula: `T=2pisqrt(L/g)`
`T=2xx3.14xxsqrt(1.005/9.8)`
`=2.012 s`
The period of a seconds pendulum is 2 second.
Hence, the given pendulum clock will lose 0.012s in 2.012s (during summer).
Loss in period per day
`ΔT=(24xx3600xx0.012)/2.012`
`DeltaT=515.3s`
The clock will gain or lose 515.3 s in one day.
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