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Question
AB is a pole of height 6 m standing at a point B and CD is a ladder inclined at angle of 600 to the horizontal and reaches upto a point D of pole . If AD = 2.54 m , find the length of the ladder.
Solution
In the given figure,
AB = AD + DB = 6 m
Given: AD = 2.54 m
⇒ 2.54 m + DB = 6 m
⇒ DB = 3.46 m
Now, in the right triangle BCD,
`(BD)/(CD)=sin 60°`
`⇒ (3.46 m)/(CD)=sqrt3/2`
`⇒(3.46 m)/(CD)=1.73/2`
`⇒ CD= (2xx3.46m)/1.73`
`⇒ CD=4 m`
Thus, the length of the ladder CD is 4 m.
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