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Abcd is a Rectangle with ∠Adb = 55°, Calculate ∠Abd. - Mathematics

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Question

ABCD is a rectangle with ∠ADB = 55°, calculate ∠ABD.

Sum

Solution


In ΔABD,
∠ADB = 55°
∠DAB = 90°  ...(in rectangle angle between two sides is 90°)
∠ADB + ∠DAB + ∠ABD = 180°
55° + 90° + ∠ABD = 180°
∠ABD = 180° - 145°
∠ABD = 35°.

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Diagonal Properties of Different Kinds of Parallelograms
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Chapter 19: Quadrilaterals - Exercise 19.2

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Frank Mathematics [English] Class 9 ICSE
Chapter 19 Quadrilaterals
Exercise 19.2 | Q 2
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