English

Activation energy of a chemical reaction can be determined by ______. - Chemistry

Advertisements
Advertisements

Question

Activation energy of a chemical reaction can be determined by ______.

Options

  • determining the rate constant at standard temperature.

  • determining the rate constants at two temperatures.

  • determining probability of collision.

  • using catalyst.

MCQ
Fill in the Blanks

Solution

Activation energy of a chemical reaction can be determined by determining the rate constants at two temperatures.

Explanation:

log k2k1=Ea2.303R(1T1-1T2)

Where, Ea =  activation energy

T2 = higher temperature

T1 = lower temperature

k1 = rate constant at temperature T1

k2 = rate constant at temperature T2

This equation is known as Arrhenius equation.

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Chemical Kinetics - Exercises [Page 47]

APPEARS IN

NCERT Exemplar Chemistry [English] Class 12
Chapter 4 Chemical Kinetics
Exercises | Q I. 3. | Page 47

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Consider a certain reaction AProducts with k = 2.0 × 10−2 s−1. Calculate the concentration of A remaining after 100 s if the initial concentration of A is 1.0 mol L−1.


The decomposition of A into product has value of k as 4.5 × 103 s−1 at 10°C and energy of activation 60 kJ mol−1. At what temperature would k be 1.5 × 104 s−1?


The rate constant of a first order reaction are 0.58 S-1 at 313 K and 0.045 S-1 at 293 K. What is the energy of activation for the reaction?


Explain the following terms :

Half life period of a reaction (t1/2)

 

 

The decomposition of a hydrocarbon has value of rate constant as 2.5×104s-1 At 27° what temperature would rate constant be 7.5×104 × 3 s-1if energy of activation is  19.147 × 103 J mol-1 ?


Consider figure and mark the correct option.


Which of the following statements are in accordance with the Arrhenius equation?

(i) Rate of a reaction increases with increase in temperature.

(ii) Rate of a reaction increases with decrease in activation energy.

(iii) Rate constant decreases exponentially with increase in temperature.

(iv) Rate of reaction decreases with decrease in activation energy.


The equation k = (6.5×1012s-1)e-26000 K/T is followed for the decomposition of compound A. The activation energy for the reaction is ______ kJ mol-1. (Nearest integer) (Given: R = 8.314 JK-1 mol-1)


An exothermic reaction X → Y has an activation energy 30 kJ mol-1. If energy change ΔE during the reaction is - 20 kJ, then the activation energy for the reverse reaction in kJ is ______.


A schematic plot of ln Keq versus inverse of temperature for a reaction is shown below

The reaction must be:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×
Our website is made possible by ad-free subscriptions or displaying online advertisements to our visitors.
If you don't like ads you can support us by buying an ad-free subscription or please consider supporting us by disabling your ad blocker. Thank you.