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Question
Answer the following:
Find the Cartesian coordinates of the point on the parabola y2 = 12x whose parameter is −3
Solution
The equation of the parabola is y2 = 12x.
Comparing with y2 = 4ax, we get,
4a = 12
∴ a = 3
The point with parameter t is
P(t) ≡ (at2, 2at)
P(– 3) = (3 × 9, 2 × 3 × (– 3))
= (27, –18)
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