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Answer the following in one or two sentences. Comment on the statement: no work is involved in an expansion of gas in a vacuum. - Chemistry

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Question

Answer the following in one or two sentences.

Comment on the statement:

no work is involved in an expansion of gas in a vacuum.

Short Note

Solution

  1. A free expansion means expansion against zero opposing force. Such expansion occurs in a vacuum.
  2. When the gas expands in a vacuum, there is no opposing force, that is, Pext = 0. The work done by a system during such expansion is
    W = - Pext Δ V = 0
    Thus, no work is done when the gas expands freely in a vacuum.

Note: Units of energy and work:

1 J = 1 kg m2 s-2 = 1 Pa m3

1 Pa = 1 kg m-1 s-2

From the equation, W = – Pext∆V

If the pressure is expressed in bar and ΔV in dm3, then the work has the units of bar dm3.

1 bar = 105 Pa = 105 kg m–1 s–2

1 dm3 bar = dm3 × 105 kg m-1 s-2

= m3 × 10-3 × 105 kg m-1 s-2

= 100 kg m2 s-2 = 100 J

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Expression for Pressure-volume (PV) Work
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Chapter 4: Chemical Thermodynamics - Exercises [Page 87]

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Balbharati Chemistry [English] 12 Standard HSC
Chapter 4 Chemical Thermodynamics
Exercises | Q 2.1 | Page 87

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