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Question
OACB is a quadrant of a circle with centre O and its radius is 3.5 cm. If OD = 2 cm. find the area of
- quadrant OACB
- the shaded region.
Solution
i . Area of the quadrant OACB `=(1/4xx22/7xx3.5xx3.5) "cm"^2 `
`=(1/4xx22/7xx35/10xx35/10) "cm"^2`
`=77/8 "cm"^2`
= 9.625 cm2
ii . Area of the shaded region = Area of the quadrant OACB - Area of ΔAOD
`=|(77/8)- (1/2xx3.5xx2)|"cm"^2`
`= (77/8 - 35/10) "cm"^2 `
`=49/8 "cm"^2`
= 6.125 cm2
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