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By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = 4x3 – 12x2 + 14x – 3, g(x) = 2x – 1 - Mathematics

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Question

By Remainder Theorem find the remainder, when p(x) is divided by g(x), where p(x) = 4x3 – 12x2 + 14x – 3, g(x) = 2x – 1

Sum

Solution

Given, p(x) = 4x3 – 12x2 + 14x – 3 and g(x) = 2x – 1

Here, zero of g(x) is `1/2`.

When we divide p(x) by g(x) using remainder theorem, we get the remainder `p(1/2)`.

∴ `p(1/2) = 4(1/2)^3 - 12(1/2)^2 + 14(1/2) - 3`

= `4 xx 1/8 - 12 xx 1/4 + 14 xx 1/2 - 3`

= `1/2 - 3 + 7 - 3`

= `1/2 + 1`

= `(1 + 2)/2`

= `3/2`

Hence, remainder is `3/2`.

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Chapter 2: Polynomials - Exercise 2.3 [Page 20]

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NCERT Exemplar Mathematics [English] Class 9
Chapter 2 Polynomials
Exercise 2.3 | Q 14. (iii) | Page 20
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