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Question
Calculate the total amount of heat energy required to melt 200 g of ice at 0°C to water at 100°C. (Specific latent heat of ice = 336 Jg-1, specific heat capacity of water = 4.2 Jg-1 °C-1)
Solution
200 g of ice at 0°C
Q1 = mLf
200 g of H2O at 0°C
Q2 = m × c × θR
200 g of H2O at 100°C
Total heat required
Q = Q1 + Q2
= mLf + m × c × θR
= (200 × 336) + (200 × 4·2 × 100)
= (67200) + (84000)
= 1,51,200 J
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