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Question
Check the ordered points (1, −1), (2, −1) is a solution of 2x + 3y − 6 ≤ 0
Solution
Given inequality: 2x + 3y – 6 ≤ 0
i.e., 2x + 3y ≤ 6 .......(i)
Consider point (1, –1).
Putting x = 1 and y = –1 in equation (i), we get
2(1) + 3(–1) = 2 – 3
= – 1 ≤ 6
which is true.
Consider point (2, –1)
Putting x = 2 and y = –1 in equation (i), we get
2(2) + 3(–1) = 4 – 3
= 1 ≤ 6
which is true.
∴ Given ordered pairs are solutions of 2x + 3y – 6 ≤ 0.
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