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Complete the following reaction sequence by writing the structural formulae of the organic compound 'A', 'B' and 'C'. -2-Bromobutane→Alc⋅KOHA→BrA2B→NaNHA2C - Chemistry

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Question

Complete the following reaction sequence by writing the structural formulae of the organic compound 'A', 'B' and 'C'.

\[\ce{2-Bromobutane->[Alc.KOH]A->[][Br2]B->[][NaNH2]C}\]

Short Note

Solution

\[\begin{array}{cc}
\phantom{.}\ce{Br}\phantom{................................................................}\ce{Br}\phantom{.............................................}\\
\phantom{...}|\phantom{..................................................................}|\phantom{................................................}\\
\ce{\underset{\text{2-Bromobutane}}{H3C - CH - CH2CH3}->[Alc.KOH][-KBr]\underset{\underset{(Major) (A)}{But-2-ene}}{H3C - CH = CH - CH3}->[Br2] H3C - CH - CH - CH3 ->[NaNH2][Double dehydrohalogen reaction] \underset{\text{But-2-yne (C)}}{H3C - C ≡ C-CH3}}\\
\phantom{.........}|\\
\phantom{................}\ce{\underset{\text{2,3-Dibromobutane (B)}}{Br}}
\end{array}\]
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Chapter 10: Halogen Derivatives - Exercises [Page 233]

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Balbharati Chemistry [English] 12 Standard HSC
Chapter 10 Halogen Derivatives
Exercises | Q 7. ii. a. | Page 233

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