Advertisements
Advertisements
Question
`"d"/"dx" (1/x)` is equal to:
Options
-\[\frac{1}{x^2}\]
-\[\frac{1}{x}\]
log x
\[\frac{1}{x^2}\]
Solution
-\[\frac{1}{x^2}\]
APPEARS IN
RELATED QUESTIONS
Evaluate the following:
`lim_(x->0) (sqrt(1+x) - sqrt(1-x))/x`
If `lim_(x->2) (x^n - 2^n)/(x-2) = 448`, then find the least positive integer n.
If f(x) = `(x^7 - 128)/(x^5 - 32)`, then find `lim_(x-> 2)` f(x)
Let f(x) = `("a"x + "b")/("x + 1")`, if `lim_(x->0) f(x) = 2` and `lim_(x->∞) f(x) = 1`, then show that f(-2) = 0
Examine the following function for continuity at the indicated point.
f(x) = `{((x^2 - 9)/(x-3) "," if x ≠ 3),(6 "," if x = 3):}` at x = 3
Find the derivative of the following function from the first principle.
log(x + 1)
Evaluate: `lim_(x->1) ((2x - 3)(sqrtx - 1))/(2x^2 + x - 3)`
If f(x) = `{(x^2 - 4x if x >= 2),(x+2 if x < 2):}`, then f(0) is
For what value of x, f(x) = `(x+2)/(x-1)` is not continuous?
`"d"/"dx"` (5ex – 2 log x) is equal to:
