Advertisements
Advertisements
Question
Diagonals of a quadrilateral ABCD bisect each other. If ∠A = 35º, determine ∠B.
Solution
Given: Diagonals of a quadrilateral ABCD bisect each other.
So, ABCD is a parallelogram.
Now, ∠A + ∠B = 180° ...[Adjacent angles of a parallelogram are supplementary]
Since, 35° + ∠B = 180°
∠B = 180° – 35°
∠B = 145°
APPEARS IN
RELATED QUESTIONS
Diagonals of a parallelogram `square`WXYZ intersect each other at point O. If ∠XYZ = 135° then what is the measure of ∠XWZ and ∠YZW?
If l(OY)= 5 cm then l(WY)= ?
The diagonals AC and BD of a parallelogram ABCD intersect each other at the point O. If ∠DAC = 32º and ∠AOB = 70º, then ∠DBC is equal to ______.
Diagonals AC and BD of a parallelogram ABCD intersect each other at O. If OA = 3 cm and OD = 2 cm, determine the lengths of AC and BD.
In a parallelogram ABCD, AB = 10 cm and AD = 6 cm. The bisector of ∠A meets DC in E. AE and BC produced meet at F. Find the length of CF.
A diagonal of a parallelogram bisects one of its angles. Show that it is a rhombus.
P and Q are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. Show that PQ is bisected at O.
ABCD is a rectangle in which diagonal BD bisects ∠B. Show that ABCD is a square.
P is the mid-point of the side CD of a parallelogram ABCD. A line through C parallel to PA intersects AB at Q and DA produced at R. Prove that DA = AR and CQ = QR.
Two sticks each of length 5 cm are crossing each other such that they bisect each other. What shape is formed by joining their endpoints? Give reason.
Two sticks each of length 7 cm are crossing each other such that they bisect each other at right angles. What shape is formed by joining their end points? Give reason.