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Differentiate the following function w.r.t.x. : 2xlogx - Mathematics and Statistics

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Question

Differentiate the following function w.r.t.x. : `2^x/logx`

Sum

Solution

Let y = `2^x/logx`

Differentiating w.r.t. x, we get

`"dy"/"dx" = "d"/"dx" (2^x/logx)`

=` (log x  d/dx (2^x) - 2^x  d/dx (logx))/(logx)^2`

= `(log x. 2^x . log 2 - 2^x . 1/x)/(log x)^2`

= `[2^x (log x log 2 - 1/x)]/(log x)^2`

shaalaa.com
Rules of Differentiation (Without Proof)
  Is there an error in this question or solution?
Chapter 9: Differentiation - Exercise 9.2 [Page 122]

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