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Question
Find `dy/dx if y = x^2 + 1/x^2`
Solution
`y = x^2 + 1/x^2`
∴ y = x2 + x–2
Differentiating w.r.t. x, we get
`dy/dx=d/dx(x^2+x^(-2))`
= `d/dx(x^2)+d/dx(x^-2)`
= 2x – 2x–3
= `2x – 2/x^3`
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