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Question
Differentiate the following function w.r.t.x. : `x/log x`
Solution
Let y =`x/log x`
Differentiating w.r.t. x, we get
`dy/dx=d/dx(x/logx)`
= `(logxd/dx(x) - xd/dx(logx))/(logx)^2`
= `(logx(1) - x(1/x))/(logx)^2`
= `(logx-1)/(logx)^2`
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