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Question
Evaluate the determinant.
`|(2,-1,-2),(0,2,-1),(3,-5,0)|`
Solution
|A| = `abs ((2,-1,-2),(0,2,-1),(3,-5,0))`
`= 2|(2,-1),(-5,0)| + 1|(0,-1),(3,0)| - 2|(0,2),(3,-5)|`
= 2[2 × 0 - (-1) × (-5)] + 1[0 × 0 - (-1) × 3] - 2[0 × (-5) - 2 × 3]
= 2(0 - 5) + 1(0 + 3) - 2(0 - 6)
= -10 + 3 + 12
= 5
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