Advertisements
Advertisements
Question
Find the centroid of the triangle whosw vertices is (1,4), (-1,1) and (3,2) .
Solution
We know that the coordinates of the centroid of a triangle whose vertices are
`(x_1,y_1),(x_2,y_2) (x_3,y_3)`are
`((x_1+x_2+x_3)/3,(y_1+y_2+y_3)/3)`
so, the coordinates of the centroid of a triangle whose vertices are
(1,4),(-1,-1) and (3,-2) are `((1-1+3)/3,(4-1-2)/3)`
`=(1,1/3)`
APPEARS IN
RELATED QUESTIONS
The coordinates of A, B, C are (6, 3), (–3, 5) and (4, – 2) respectively and P is any point (x, y). Show that the ratio of the areas of triangle PBC and ABC is
prove that the points A (7, 10), B(-2, 5) and C(3, -4) are the vertices of an isosceles right triangle.
Find the centroid of ΔABC whose vertices are A(-1, 0) B(5, -2) and C(8,2)
Show that the following points are collinear:
A(5,1), B(1, -1) and C(11, 4)
For what value of y, are the points P(1, 4), Q(3,y) and R(-3, 16) are collinear ?
Find the value of p for which the points (−5, 1), (1, p) and (4, −2) are collinear.
In ∆PQR, PR = 8 cm, QR = 4 cm and PL = 5 cm. 
Find:
(i) the area of the ∆PQR
(ii) QM.
The table given below contains some measures of the right angled triangle. Find the unknown values.
| Base | Height | Area |
| ? | 12 m | 24 sq.m |
A field is in the shape of a right angled triangle whose base is 25 m and height 20 m. Find the cost of levelling the field at the rate of ₹ 45 per sq.m2
The points A(2, 9), B(a, 5) and C(5, 5) are the vertices of a triangle ABC right angled at B. Find the values of a and hence the area of ∆ABC.
