Advertisements
Advertisements
Question
Find the 5th term of the G.P. `5/2, 1, .........`
Solution
First term (a) = `5/2`
And common ratio (r) = `1/(5/2) = 2/5`
Now tn = arn – 1
`=>` 5th term = t5
= `5/2 xx (5/2)^(5 - 1)`
= `5/2 xx (2/5)^4`
= `(2/5)^3`
= `8/125`
APPEARS IN
RELATED QUESTIONS
Find, which of the following sequence from a G.P. :
8, 24, 72, 216, .............
Which term of the G.P.:
`-10, 5/sqrt(3), -5/6,....` is `-5/72`?
Second term of a geometric progression is 6 and its fifth term is 9 times of its third term. Find the geometric progression. Consider that each term of the G.P. is positive.
The fifth, eight and eleventh terms of a geometric progression are p, q and r respectively. Show that : q2 = pr.
Q 5
If a, b and c are in G.P., prove that : log a, log b and log c are in A.P.
Q 2
Q 7
The first two terms of a G.P. are 125 and 25 respectively. Find the 5th and the 6th terms of the G.P.
Find the sum of the sequence `-1/3, 1, -3, 9, ..........` upto 8 terms.
