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Question
Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0.
Solution
Since line is parallel to
3x + 5y + 15 = 0
5y = -3x - 15
y = `(-3)/(5) x - 3`
∴ m1 = `(-3)/(5)`
m1 = m2 ...(∵ lines are parallel)
∴ m2 = `(-3)/(5)`
and passing point = (0, 4)
Equation of line
y - y1 = m(x - x1)
⇒ y - 4 = `(-3)/(5)(x - 0)`
⇒ 5y - 20 = -3x
⇒ 3x + 5y = 20.
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