Advertisements
Advertisements
Question
Find the unknown marked angles in the given figure:
Solution
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
k°+ k°+ k°= 180°
⇒ 3k° = 180°
⇒ k° =`(180°)/3=60°`
Hence ∠A = k° = 60°, ∠B = k° = 60°
and ∠C = k° = 60°
APPEARS IN
RELATED QUESTIONS
Can a triangle have All angles less than 60° Justify your answer in case.
In ΔABC, if bisectors of ∠ABC and ∠ACB intersect at O at angle of 120°, then find the measure of ∠A.
Find the value of the angle in the given figure:
Calculate the angles of a triangle if they are in the ratio 4: 5: 6.
Can a triangle together have the following angles?
55°, 55° and 80°
Can 30°, 60° and 90° be the angles of a triangle?
Q is a point on the side SR of a ∆PSR such that PQ = PR. Prove that PS > PQ.
Bisectors of the angles B and C of an isosceles triangle with AB = AC intersect each other at O. BO is produced to a point M. Prove that ∠MOC = ∠ABC.
AB and CD are the smallest and largest sides of a quadrilateral ABCD. Out of ∠B and ∠D decide which is greater.
Can we have two acute angles whose sum is a reflex angle? Why or why not?