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Question
Find the value, if it exists. If not, give the reason for non-existence
`sin^-1 [sin 5]`
Solution
`- pi/2 ≤ sin^-1 5 ≤ pi/2`
`- 3 pi/2 ≤ 5 ≤ 2pi`
`- pi/2 ≤ 5 - 2pi ≤ 0 ≤ pi/2`
sin(5 – 2π) = sin 5
sin–1(sin 5) = 5 – 2π
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