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Question
Find the value of x in the given triangle
Solution
In ∆ABC, given B = 3x – 8°
∠XAZ = ∠BAC ...[∵ vertically opposite angles]
8x + 7 + ∠BAC
i.e., In ∆ABC, ∠A = 8x + 7
Exterior angle ∠XCY = 120°
Exterior angle is equal to the sum of the interior opposite angles
∠A + ∠B = 120°
8x + 7 + 3x – 8 = 120°
8x + 3x = 120° + 8 – 7
11x = 121°
x = `(121^circ)/11`
x = 11°
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