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Find the Vector Equation of the Line Passing Through (1, 2, 3) and Parallel to the Planes Vecr = (Hati - Hatj + 2hatk) = 5`And Vecr.(3hati + Hatj + Hatk) = 6 - Mathematics

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Question

Find the vector equation of the line passing through (1, 2, 3) and parallel to the planes `vecr = (hati - hatj + 2hatk)  = 5`and `vecr.(3hati + hatj + hatk) = 6`

Solution

Let the required line be parallel to vector `vecb` given by,

`vecb = b_1hati + b_2hatj + b_3hatk`

The position vector of the point (1, 2, 3) is `veca = hati + 2hatj + 3hatk`

The equation of line passing through (1, 2, 3) and parallel to `vecb`is given by,

This is the equation of the required line.

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Chapter 11: Three Dimensional Geometry - Exercise 11.4 [Page 499]

APPEARS IN

NCERT Mathematics [English] Class 12
Chapter 11 Three Dimensional Geometry
Exercise 11.4 | Q 19 | Page 499

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