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Question
From adjoining figure, ∠ABC = 90°, ∠DCB = 90°, AB = 6, DC = 8, then `("A"(Δ"ABC"))/("A"(Δ"BCD"))` = ?
Solution
ΔABC and ΔBCD have same base BC.
∴ `("A"(Δ"ABC"))/("A"(Δ"BCD")) = "AB"/"DC"` ...[Triangles having equal base]
∴ `("A"(Δ"ABC"))/("A"(Δ"BCD")) = 6/8`
∴ `("A"(Δ"ABC"))/("A"(Δ"BCD")) = 3/4`
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