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Question
From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semicircular portion with BC as diameter is cut off. Find the area of the remaining paper.
Solution
We know that the opposite sides of rectangle are equal
∴ AD = BC = 28 cm
Now, Radius of semicircular portion` =1/2"BC = 14 "cm" `
∴ Area of remaining paper = Area of rectangular sheet −Area of semicircular portion
`= 40xx28-1/2(22/7xx14xx14)`
= 1120 - 308
= 812 cm2
Hence, the area of the remaining paper is 812 cm2
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