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Question
From the top of a rock `50sqrt(3)` m high, the angle of depression of a car on the ground is observed to be 30°. Find the distance of the car from the rock
Solution
Let the distance of the car from the rock is x m
In the right ∆ABC, tan 30° = `"AB"/"BC"`
`1/sqrt(3) = (50sqrt(3))/x`
x = `50sqrt(3) xx sqrt(3)`
= 50 × 3
= 150 m
∴ Distance of the car from the rock = 150 m
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[OR]
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