English

Give reasons for need of Hybridization - Chemistry

Advertisements
Advertisements

Question

Give reasons for need of Hybridization

Answer in Brief

Solution

The concept of hybridization was introduced because the valence bond theory failed to explain the following points:

  1. Valencies of certain elements:
    The maximum number of covalent bonds which an atom can form equals the number of unpaired electrons present in its valence shell. However, valence bond theory failed to explain how beryllium, boron, and carbon form two, three, and four covalent bonds respectively.
    a. Beryllium: The electronic configuration of beryllium is 1s2 2s2. The expected valency is zero (as there is no unpaired electron) but the observed valency is 2 as in BeCl2.
    b. Boron: The electronic configuration of boron is 1s2 2s2 \[\ce{2p^1_{{x}}}\]. The valency is expected to be 1 but it is 3 as in BF3.
    c. Carbon: The electronic configuration of carbon is 1s2 2s2 \[\ce{2p^1_{{x}}}\] \[\ce{2p^1_{{y}}}\]. The valency is expected to be 2, but the observed valency is 4 as in CH4.
  2. The shapes and geometry of certain molecules:
    The valence bond theory cannot explain shapes, geometries, and bond angles in certain molecules.
    e.g. a. Tetrahedral shape of a methane molecule.
    b. Bond angles in molecules like NH3 (107°18’) and H2O (104°35’).
    However, the valency of the above elements and the observe structural properties of the above molecules can be explained by the concept of hybridization. These are the reasons for need of the concept of hybridization.
shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Chemical Bonding - Exercises [Page 79]

APPEARS IN

Balbharati Chemistry [English] 11 Standard
Chapter 5 Chemical Bonding
Exercises | Q 3. (E) | Page 79

RELATED QUESTIONS

Explain the formation of H2 molecule on the basis of valence bond theory.


Draw diagram for bonding in ethene with sp2 Hybridisation.


Draw an orbital diagram of Fluorine molecule


Display electron distribution around the oxygen atom in the water molecule and state the shape of the molecule, also write the H-O-H bond angle.


Give a reason for the sigma (σ) bond is stronger than the Pi (π) bond.


Give a reason for carbon is tetravalent in nature.


Identify the type of overlap present in F2. Explain diagrammatically.


Identify the type of overlap present in H-F molecule. Explain diagrammatically.


The ratio of number of sigma (σ) and pi (л) bonds in 2- butynal is ______.


Which one of the following is the likely bond angles of sulphur tetrafluoride molecule?


According to Valence bond theory, a bond between two atoms is formed when ______.


In ClF3, NF3 and BF3 molecules the chlorine, nitrogen and boron atoms are ______.


The correct order of O – O bond length in hydrogen peroxide, ozone and oxygen is


Among the following, the compound that contains, ionic, covalent and Coordinate linkage is ______.


Which bond is stronger σ or π? Why?


Considering x-axis as the molecular axis which out of the following will form a sigma bond.

2px and 2pz


Ethene molecule has ____________ sp2 -s σ bond(s), ____________ sp2 -sp2 σ bond(s) and ____________ p-p π bond(s).


Which of the following molecule contain 50% p-character of hybrid orbital in C atom?


The number of sigma bonds in paracetamol is ____________.


The number of sigma bonds in vanillin is ____________.


The overlap of orbitals involved in the formation of C - Br bond in vinyl bromide is ______.


If the electronic configuration of an element is 1s2 2s2 2p6 3s2 3p6 3d2 4s2, the four electrons involved in chemical bond formation will be ______.


Match List - I with List - II.

List - I List - II
(a) \[\ce{PCl5}\] (i) Square pyramidal
(b) \[\ce{SF6}\] (ii) Trigonal planar
(c) \[\ce{BrF5}\] (iii) Octahedral
(d) \[\ce{BF3}\] (iv) Trigonal bipyramidal

Choose the correct answer from the options given below.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×