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Question
Given A = `[(3, -2),(-1, 4)]`, B = `[(6),(1)]`, C = `[(-4),(5)]` and D = `[(2),(2)].` Find : AB + 2C – 4D
Solution
AB = `[(3, -2),(-1, 4)][(6),(1)] = [(18 - 2),(-6 + 4)] = [(16),(-2)]`
2C = `2[(-4),(5)]=[(-8),(10)]`
4D = `4[(2),(2)]=[(8),(8)]`
Now, AB + 2C – 4D = `[(16),(-2)] + [(-8),(10)] - [(8),(8)]`
= `[(16 - 8 - 8),(-2 + 10 - 8)]`
= `[(0),(0)]`
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