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Question
Given matrix A = `[(4sin30^@,cos0^@), (cos0^@,4sin30^@)] and B = [(4), (5)]` If AX = B.
Find the matrix 'X'
Solution
Let the matrix X = `[(x), (y)]`
AX = B
`=> [(4sin30^@,cos0^@), (cos0^@,4sin30^@)][(x), (y)] = [(4), (5)]`
`=> [(4(1/2),1), (1,4(1/2))][(x), (y)] = [(4), (5)]`
`=> [(2,1), (1,2)][(x), (y)] = [(4), (5)]`
`=> [(2x+y), (x+2y)] = [(4), (5)]`
`=> 2x + y = 4 .............(1)
x + 2y = 5 .........(2)
Multiplying (1) by 2, we get
4x + 2y = 8 ….(3)
Subtracting (2) from (3), we get
3x = 3
⇒ x = 1
Substituting the value of x in (1), we get
2(1) + y = 4
⇒ 2 + y = 4
⇒ y = 2
Hence, the matrix X = `[(x), (y)] = [(1), (2)]`
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