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Question
If A = `[(cos alpha, sin alpha),(-sin alpha, cos alpha)]`, then A10 = ______
Options
`[(cos10 alpha, -sin10 alpha),(sin10 alpha, cos10 alpha)]`
`[(cos10 alpha, sin10 alpha),(-sin10 alpha, cos10 alpha)]`
`[(cos10 alpha, sin10 alpha),(-sin10 alpha, -cos10 alpha)]`
`[(cos10 alpha, -sin10 alpha),(-sin10 alpha, -cos10 alpha)]`
Solution
`bb([(cos10 alpha, sin10 alpha),(-sin10 alpha, cos10 alpha)])`
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