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Question
If the coordinates of one end of a diameter of a circle is (3, 4) and the coordinates of its centre is (−3, 2), then the coordinate of the other end of the diameter is
Options
(0, −3)
(0, 9)
(3, 0)
(−9, 0)
Solution
(−9, 0)
Explanation;
Hint:
Let the other end of the diameter be (a, b)
Mid-point of a line =
`((x_1 + x_2)/2, (y_1 + y_2)/2)`
(−3, 2) = `(3 + "a")/2, (4 + "b")/2`
`(3 + "a")/2` = −3
3 + a = −6
a = −6 – 3 = −9
and
`(4 + "b")/2` = 2
4 + b = 4
b = 4 – 4 = 0
The other end is (−9, 0)
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