Advertisements
Advertisements
Question
In the adjoining figure line RP ||line MS , line DK is a transversal . If ∠DHP = 85° find ∠RHG and ∠HGS.
Solution
∠ RHG = ∠ DHP .................(Opposite angles)
= 85˚
∠ HGS = ∠ DHP ................ (Corresponding angles)
= 85˚
APPEARS IN
RELATED QUESTIONS
Write the equation of the line passing through the pair of points (2, 3) and (4, 7) in the form of y = mx + c.
If (4,-3) is a point on the line AB and slope of the line is (-2), write the equation of the line AB.
Write the equation of each of the following lines:
- The x-axis and the y-axis.
- The line passing through the origin and the point (-3, 5).
- The line passing through the point (-3, 4) and parallel to X-axis.
Find the slope and y-intercept of the line:
y = 4
Find the slope and y-intercept of the line:
3x – 4y = 5
Find the equation of the line passing through (−2, 1) and perpendicular to 4x + 5y = 6.
Find the equation of the perpendicular bisector of the line segment obtained on joining the points (6, −3) and (0, 3).
- Write down the equation of the line AB, through (3, 2) and perpendicular to the line 2y = 3x + 5.
- AB meets the x-axis at A and the y-axis at B. Write down the co-ordinates of A and B. Calculate the area of triangle OAB, where O is the origin.
The points A, B and C are (4, 0), (2, 2) and (0, 6) respectively. Find the equations of AB and BC. If AB cuts the y-axis at P and BC cuts the x-axis at Q, find the co-ordinates of P and Q.
Match the equations A, B, C and D with the lines L1, L2, L3 and L4, whose graphs are roughly drawn in the given diagram.
A ≡ y = 2x;
B ≡ y – 2x + 2 = 0;
C ≡ 3x + 2y = 6;
D ≡ y = 2
Find the equation of the line which is perpendicular to the line `x/a - y/b = 1` at the point where this line meets y-axis.
Find the point on the X–axis which is equidistant from A(–3, 4) and B(1, –4).
Find Equation of CD
Find the equation of the line that has x-intercept = –3 and is perpendicular to 3x + 5y = 1.
Find the equation of line through the intersection of lines 2x – y = 1 and 3x + 2y = –9 and making an angle of 30° with positive direction of x-axis.
Find the equation of the line through the points A(–1, 3) and B(0, 2). Hence, show that the point A, B and C(1, 1) are collinear.
Three vertices of a parallelogram ABCD taken in order are A(3, 6), B(5, 10) and C(3, 2), find:
- the co-ordinates of the fourth vertex D.
- length of diagonal BD.
- equation of side AB of the parallelogram ABCD.
If (4,-3) is a point on line 5x +8y = c, find the value of c.
Find the equation of the line passing through the points (4,-5) and (-1,-2).
A line segment joining P(2, –3) and Q(0, –1) is cut by the x-axis at the point R. A line AB cuts the y-axis at T(0, 6) and is perpendicular to PQ at S.
Find the:
- equation of line PQ
- equation of line AB
- coordinates of points R and S.
