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Question
Find the equation of the line passing through the points (4,-5) and (-1,-2).
Solution
Equation of line passing through points (x1,y1) and (x2,y2) is given by
`(x - x_1)/(x_1 - x_2) = (y - y_1)/(y_1 - y_2)`
Here (x1,y1) = (4,-5) and (x2,y2) = (-1,-2)
Equation of line passing through (4,-5) and (-1,-2) is given by
`(x - 4)/(4 - (-1)) = (y - (-5))/((-5) - (-2))`
∴ `(x - 4)/5 = (y + 5)/-3`
∴ (-3)(x-4) = 5(y + 5)
∴ - 3x + 12 = 5y + 25
∴ 12 – 25 = 5y + 3x
∴ 3x + 5y = - 13
∴ 3x + 5y + 13 = 0
Therefore equation of line passing through (4,-5) and (-1,-2) is 3x + 5y + 13 = 0
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