Advertisements
Advertisements
Question
In the below Fig, OA and OB are opposite rays.
If y = 35°, what is the value of x?
Solution 1
Given that if y = 35°
`∠`AOC + `∠`BOC = 180°
(2 y + 5) + 3x = 180°
(2 (35) + 5) + 3x = 180°
(70 + 5) + 3x = 180°
3x = 180° - 75°
3x = 105°
x = 35°
x = 35°
Solution 2
In figure:
Since OA and OB are opposite rays. Therefore, AB is a line. Since, OC stands on line AB.
Thus,∠AOCand ∠BOC form a linear pair, therefore, their sum must be equal to180°.
Or, we can say that
∠AOC + ∠BOC = 180°
From the given figure:
∠AOC= (2y + 5)and ∠BOC = 3x
On substituting these two values, we get
`(2y + 5) + 3x = 180`
`3x + 2y = 180 -5`
3x + 2y = 175 ...(i)
On putting in y =35 in equation (A), we get:
`3x + 2(35) =175`
`3x + 70 = 175`
`3x = 175 - 70`
`3x = 105`
`x = 105/3`
`x = 35`
Hence, the value of x is 35.
APPEARS IN
RELATED QUESTIONS
Write the complement of the following angles .
30°
Write the supplement of the following angles .
54°
The measure of an angle is twice the measure of its supplementary ang Find its measure.
In the below Fig, OA and OB are opposite rays :
If x = 25°, what is the value of y?
In the below Fig, ∠AOC and ∠BOC form a linear pair. if a − 2b = 30°, find a and b.
If below fig, ∠AOF and ∠FOG form a linear pair.
∠EOB = ∠FOC = 90° and ∠DOC = ∠FOG = ∠AOB = 30°
(i) Find the measures of ∠FOE, ∠COB and ∠DOE.
(ii) Name all the right angles.
(iii) Name three pairs of adjacent complementary angles.
(iv) Name three pairs of adjacent supplementary angles.
(v) Name three pairs of adjacent angles.
In the given fig, find the values of x, y and z.
In the below, PQ || AB and PR || BC. If `∠`QPR = 102°, determine `∠`ABC. Give reasons.
In the below fig, arms BA and BC of ∠ABC are respectively parallel to arms ED and EF of
∠DEF. Prove that ∠ABC + ∠DEF = 180°.
In the given figure, if AB || HF and DE || FG, then the measure of ∠FDE is