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Question
In the given figure ABCD is quadrilateral in which diagonal BD = 24 cm, AL ⊥ BD and CM ⊥ BD such that AL = 9cm and CM = 12 cm. Calculate the area of the quadrilateral.
Solution
We have,
BD=24 cm AL=9 cm CM=12 cm AL⊥ BD and CM ⊥BD
Area of the quadrilateral = ar (Δ ABD)+ar (Δ BCD)
= `1/2xx BDxxAL+1/2 xxBDxxCM`
=`1/2xx24xx9+1/2xx24xx12`
=`108+144`
=`252 cm^2`
So, the area of the quadrilateral ABCD is 252`cm^2`
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