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Question
In the given figure, given that ∆ABC ∼ ∆PQR and quad ABCD ∼ quad PQRS. Determine the value of x, y, z in each case.
Solution
(i) We have, `Δ ABC ∼ Δ PQR `
So the ratio of the sides of the triangles will be proportional to each other.
`(AB)/(PQ)=(BC)/(QR)=(AC)/(PR)`
Therefore put the values of the known terms in the above equation to get,
`12/9=7/x=10/y`
On solving these simultaneous equations, we get
`x= 21/4`
`y = 30/4`
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