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Question
In the adjoining figure, PT is a tangent at T to the circle with centre O. If ∠TPO = 30°, find the value of x.
Solution
Given that,
PT is a tangent at T to circle
Also, ∠TPO = 30°
So, TPO is right-angled triangle with ∠T = 90°
We have, ∠POT = (180°) – (30° + 90°) = 60°
As, x + ∠POT = 180° (linear pair angles)
`\implies` x = 180° – 120° = 60°
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