Advertisements
Advertisements
Question
In the given figure, ∠ACE = 43° and ∠CAF = 62°; find the values of a, b and c.
Solution
Now, ∠ACE = 43° and ∠CAF = 62° ...[Given]
In ΔAEC
∴ ∠ACE + ∠CAE + ∠AEC = 180°
`=>` 43° + 62° + ∠AEC = 180°
`=>` 105° + ∠AEC = 180°
`=>` ∠AEC = 180° – 105° = 75°
Now, ∠ABD + ∠AED = 180° ...[Opposite angles of a cyclic quad and ∠AED = ∠AEC]
`=>` a + 75° = 180°
`=>` a = 180° – 75°
`=>` a = 105°
∠EDF = ∠BAF
∴ c = 62° ...[Angles in the alternate segments]
In ΔBAF, a + 62° + b = 180°
`=>` 105° + 62° + b = 180°
`=>` 167° + b = 180°
`=>` b = 180° – 167° = 13°
Hence, a = 105°, b = 13° and c = 62°.
APPEARS IN
RELATED QUESTIONS
A triangle ABC is inscribed in a circle. The bisectors of angles BAC, ABC and ACB meet the circumcircle of the triangle at points P, Q and R respectively. Prove that:
- ∠ABC = 2∠APQ,
- ∠ACB = 2∠APR,
- `∠QPR = 90^circ - 1/2 ∠BAC`.
The given figure shows a circle with centre O and ∠ABP = 42°.
Calculate the measure of:
- ∠PQB
- ∠QPB + ∠PBQ
In the figure, given below, CP bisects angle ACB. Show that DP bisects angle ADB.
In the figure, given below, AD = BC, ∠BAC = 30° and ∠CBD = 70°.
Find:
- ∠BCD
- ∠BCA
- ∠ABC
- ∠ADB
In the figure given alongside, AB and CD are straight lines through the centre O of a circle. If ∠AOC = 80° and ∠CDE = 40°, find the number of degrees in ∠ABC.
A triangle ABC is inscribed in a circle. The bisectors of angles BAC, ABC and ACB meet the circumcircle of the triangle at points P, Q and R respectively. Prove that :
∠ACB = 2∠APR,
If I is the incentre of triangle ABC and AI when produced meets the cicrumcircle of triangle ABC in points D . if ∠BAC = 66° and ∠ABC = 80°. Calculate : ∠IBC
In the given below the figure, AB is parallel to DC, ∠BCD = 80° and ∠BAC = 25°, Find
(i) ∠CAD, (ii) ∠CBD, (iii) ∠ADC.
In the figure, AB = AC = CD, ∠ADC = 38°. Calculate: (i) ∠ ABC, (ii) ∠ BEC.
In the given figure (drawn not to scale) chords AD and BC intersect at P, where AB = 9 cm, PB = 3 cm and PD = 2 cm.
- Prove that ΔAPB ~ ΔCPD.
- Find the length of CD.
- Find area ΔAPB : area ΔCPD.