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Question
Let A = `[(4, -2),(6, -3)]`, B = `[(0, 2),(1, -1)]` and C = `[(-2, 3),(1, -1)]`. Find A2 – A + BC
Solution
A2 = `[(4, -2),(6, -3)][(4, -2),(6, -3)]`
= `[(16 - 12, -8 + 6),(24 - 18, -12 + 9)]`
= `[(4, -2),(6, -3)]`
BC = `[(0, 2),(1, -1)][(-2, 3),(1, -1)]`
= `[(0 + 2, 0 - 2),(-2 - 1, 3 + 1)]`
= `[(2, -2),(-3, 4)]`
Given, A2 – A + BC
= `[(4, -2),(6, -3)] - [(4, -2),(6, -3)] + [(2, -2),(-3, 4)]`
= `[(0, 0),(0, 0)] + [(2, -2),(-3, 4)]`
= `[(2, -2),(-3, 4)]`
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