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Question
Middle term in the expansion of (a3 + ba)28 is ______.
Solution
Middle term in the expansion of (a3 + ba)28 is `""^28"C"_14 a^56 b^14`.
Explanation:
Number of term in the expansion (a3 + ba)28
= 28 + 1
= 29 (odd)
∴ Middle term = `(29 + 1)/2` = 15th term
∴ T15 = T14+1
= `""^28"C"_14 (a^3)^(28 - 14) * (ba)^14`
= `""^28"C"_14 (a)^42 * b^14 * a^14`
= `""^28"C"_14 a^56b^14`.
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