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Simplify: (3a + 2b - C)(9a2 + 4b2 + C2 - 6ab + 2bc +3ca) - Mathematics

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Question

Simplify:
(3a + 2b - c)(9a2 + 4b2 + c2 - 6ab + 2bc +3ca)

Sum

Solution

(3a + 2b - c)(9a2 + 4b2 + c2 - 6ab + 2bc +3ca)
= 3a(9a2 + 4b2 + c2 - 6ab + 2bc + 3a) + 2b (9a2 + 4b2 + c2 - 6ab + 2bc + 3ca) - c(9a2 + 4b2 + c2 - 6ab + 2bc + 3ca)
= 27a3 + 12ab2 + 3ac2 - 18a2b + 6abc + 9a2c + 18a2b + 8b3 + 2bc2 - 12ab2 + 4b2c + 6abc - 9a2c - 4b2c - c3 + 6abc - 2bc2 - 3ac2
= 27a3 + 8b3 - c3 + 18abc.

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Chapter 4: Expansions - Exercise 4.2

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 4 Expansions
Exercise 4.2 | Q 24.11
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