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Question
Write the following cube in expanded form:
`[3/2x+1]^3`
Solution
(x + y)3 = x3 + y3 + 3xy(x + y)
Using Identity
`[3/2x + 1]^3 = (3/2x)^3 + (1)^3 + 3(3/2x)(1)(3/2x + 1)`
= `27/8x^3 + 1 + 9/2x[3/2x + 1]`
= `27/8x^3 + 1 + 27/4x^2 + 9/2x`
= `27/8x^3 + 27/4x^2 + 9/2x + 1`
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