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Write the following cube in expanded form: [x-23y]3 - Mathematics

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Question

Write the following cube in expanded form:

`[x-2/3y]^3`

Sum

Solution

(x - y)3 = x3 - y3 - 3xy(x - y)

Using Identity

`[x - 2/3y]^3 = x^3 - (2/3y)^3 - 3(x)(2/3y)(x - 2/3y)`

= `x^3 - 8/27y^3 - 2xy(x - 2/3y)`

= `x^3 - 8/27y^3 - 2x^2y + 4/3xy^2`

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Chapter 2: Polynomials - Exercise 2.5 [Page 49]

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NCERT Mathematics [English] Class 9
Chapter 2 Polynomials
Exercise 2.5 | Q 6.4 | Page 49

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