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If 49a2 − B = ( 7 a + 1 2 ) ( 7 a − 1 2 ) Then the Value of B is - Mathematics

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Question

If 49a2 − b = \[\left( 7a + \frac{1}{2} \right) \left( 7a - \frac{1}{2} \right)\] then the value of b is 

Options

  • 0

  • \[\frac{1}{4}\]

  • \[\frac{1}{\sqrt{2}}\]
  • \[\frac{1}{2}\]
MCQ

Solution

We have to find the value of b

Given  `49a^2 - b = [7a + 1/2] [7a-1/2]`

Using identity  `x^2 -   y^2 = (x+y)(x-y)`

We get

`49a^2 - b = [7a+1/2] [7a - 1/2]`

`49a^2 - b = [(7a)^2 - (1/2)^2]`

`49a^2 - b = [49a^2 - 1/4]`

Equating ‘b’ on both sides we get 

` -b = -1/4`

` -b = -1/4`

Hence the value of b is `1/4`.

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Chapter 4: Algebraic Identities - Exercise 4.7 [Page 32]

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RD Sharma Mathematics [English] Class 9
Chapter 4 Algebraic Identities
Exercise 4.7 | Q 27 | Page 32

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