हिंदी

Write the following cube in expanded form: [x-23y]3 - Mathematics

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प्रश्न

Write the following cube in expanded form:

`[x-2/3y]^3`

योग

उत्तर

(x - y)3 = x3 - y3 - 3xy(x - y)

Using Identity

`[x - 2/3y]^3 = x^3 - (2/3y)^3 - 3(x)(2/3y)(x - 2/3y)`

= `x^3 - 8/27y^3 - 2xy(x - 2/3y)`

= `x^3 - 8/27y^3 - 2x^2y + 4/3xy^2`

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अध्याय 2: Polynomials - Exercise 2.5 [पृष्ठ ४९]

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एनसीईआरटी Mathematics [English] Class 9
अध्याय 2 Polynomials
Exercise 2.5 | Q 6.4 | पृष्ठ ४९

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