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Question
Solve for x, the inequality given below.
`4/(x + 1) ≤ 3 ≤ 6/(x + 1)`, (x > 0)
Solution
`4/(x + 1) ≤ 3 ≤ 6/(x + 1)`
Multiplying each term by (x + 1),
⇒ 4 ≤ 3(x + 1) ≤ 6
⇒ 4 ≤ 3x + 3 ≤ 6
Subtracting each term by 3, we get,
⇒ 1 ≤ 3x ≤ 3
Dividing each term by 3, we get,
⇒ `(1/3)` ≤ x ≤ 1
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