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Question
The angle of depression of a car parked on the road from the top of a 150 m high tower is 30°. The distance of the car from the tower (in metres) is
`(A) 50sqrt3`
`(B) 150sqrt 3`
`(C) 150sqrt2`
`(D) 75`
Solution
Correct answer: A
Let AB be the tower and BC be distance between tower and car. Let θ be the angle of depression of the car.
According to the given information,
`In triangleABC,`
`tan theta =`
`BC=150/sqrt3=(150sqrt3)/3=50sqrt3`
Hence, distance between the tower and car is `50 sqrt3`
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