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Question
Two circles touch each other externally at P. AB is a common tangent to the circles touching them at A and B. The value of ∠ L APB is
(A) 30°
(B) 45°
(C) 60°
(D) 90°
Solution
Correct answer: D
TA = TP ⇒ ∠TAP = ∠TPA
TB = TP ⇒∠TBP = ´TPB
∠TAP + ∠TBP
Correct answer: D
TA = TP ⇒ ∠TAP = ∠TPA
TB = TP ⇒∠TBP = ´TPB
∠TAP + ∠TBP= ∠TPA + ∠TPB= ∠APB
` ∠TAP + ∠TBP+ ∠APB=180^@[because "sum of" ......180^@]`
`/_APB+/_APB=180^@`
`2/_APB=180^@`
`/_APB=90^@`
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