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Question
The angles of a hexagon are (2x + 5)°, (3x - 5)°, (x + 40)°, (2x + 20)°, (2x + 25)° and (2x + 35)°. Find the value of x.
Solution
A hexagon has 6 sides
∴ Sum of interior angles
= (n - 2) x 180°
= (6 - 2) x 180°
= 4 x 180°
= 720°
Given the angle of a hexagon are (2x + 5)°, (3x - 5)°, (x + 40)°, (2x + 20)°, (2x + 25)° and (2x + 35)°
∴ (2x + 5)°, + (3x - 5)°, + (x + 40)°, + (2x + 20)°, + (2x + 25)° +(2x + 35)° = 720
⇒ 12x + 120° = 720°
⇒ x = 50°.
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